
« #4 : September 21, 2007, 12:25:30 PM From Rajesh» 

largest side of square = sqrt(9/8) = 3/[2*sqrt2] units..
let 'O' be the origin..A(1,0,0), B(1,1,0), C(0,1,0), O'(0,0,1),A'(1,0,1), B'(1,1,1), C'(0,1,1) now take points P(3/4,0,0) on OA Q(0,3/4,0) on OC R(1/4,1,1) on C'B' S(1,1/4,1) on A'B' now for the square PQRS u can check PQ=QR=RS=SP=3/[2*sqrt2] and also from vector or 3D check that PQ is perpendicular to QR and PS and RS is perpendicular to PS and QR.
so the side PQ = sqrt(9/8) units and area of that square = 9/8 sqr unit
what u say prateek....
